易錯(cuò)的if語句

#include <stdio.h>int main(){int a=20;if (1 <= a <= 10)//1<=20為真，結(jié)果為1,1<=10為真{printf("in range\n");}else{printf("out of range\n");}return 0;}

    結(jié)果：

    in range

    請按任意鍵繼續(xù). . .